Ok I need some people to do a voice over narration thingy to
demonstrate how to do the quadratic formula. I need more than
one person to give it some variation. So if you're interested...
Requirements ::
Please talk really clearly (without
over enunciating)
Pause whenever you see a comma you know the proper way and stuff
comments begin with // and are not in the actual speech
Pause between sentences for about 3-5 seconds because I will cut
and edit the audio into different tracks
Speech ::
"
Quote:
To begin, make sure you have set up the equation properly...
x= (-(b) +/- Sqrt( b^2 -4 (a)(c)))/(2*a) //read as X equals negative B plus or minus the square root of B squared minus 4 times A times C ALL over 2 times A
Now, you input your variables A, B, and C.
Remember that at the beginning it is Negative B, as in -1*B
We then solve for the discriminant (that is the expression under the radical).
Multiply A times C, then take that product and multiply it by negative four.
Then we square b, and add the two expressions.
Get the square root of the number.
Multiply your A times 2.
Next, we must separate the equation into two separate equations.
Then we reduce.
We are done.
//Ok that was the base now we have to go ever the dependent stuff
minus
add
divide
multiply
square root
square
i
You will notice that our discriminant is negative. It is impossible to get the square root of a negative number. We must make it positive, and add an i to the end of it.
The square root of this discriminant is not an integer (it has a decimal) so it is appropriate, in most cases, to leave it as the square root of the discriminant.
Hopefully, you remembered to include the i in the final solution, because if you didn't then your answer is wrong.
Now, if the discriminant is positive you will get two real numbers, if it is negative you will get two complex numbers, and if it is 0 then you will get 1 repeating real number.
Would you like to hear more about 'i?'
Okay.
I is an imaginary number; i equals the square root of -1.
So you can deduce that i^2 //i squared
equals 1, this is important later on.
You cannot get the square-root of a negative and expect to come up with anything sensible, or so you have been told thus far.
In reality, you can, take the square root of a negative number, using i.
YOU MUST ALWAYS DO THE i-PART FIRST!!!
You deal with i just as if it were x, except for the fact that x^2 is just x^2, but i^2 is –1 //x squared and i squared
More help with 'i.'
"
Then you can upload the audio here (it can be any format, but preferably in .wav).
And, on a less serious note,
this, and
this.
http://www.somethingawful.com/flash/shmorky/babby.swf
using Sprinkles.Math
using Sprinkles.Common
using Sprinkles.Misc
using System.Security.Cryptography
